(1) Find the average of data points: (18+22+22+24+33+36)/6 = 25.83
(2) Next you need to calculate the sample variance subtract the average from each data point then square it, find the total & divide by 1 less the number of data points:
(18 - 25.83)2 = 61.309
(22 - 25.83)2 = 14.669
(22 - 25.83)2 = 14.669
(24 - 25.83)2 = 3.349
(33 - 25.83)2 = 51.409
(36 - 25.83)2 = 103.429
Var. = (61.309+14.669+14.669+3.349+51.409+103.429)/5 = 49.767
(3) The standard deviation is the positive square root of the sample variance:
STD = SQROOT (49.767) = 7.05
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64.
$18,000,000,000.00 or $18 billion
16
It is: 0.000018
18.00
The range is 9 and 3.01 is the standard deviation.
The standard deviation is the square root of the variance. In this case, the square root of 324 is 18. Therefore, the standard deviation of the data values in the population is 18.
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
The range is 12 and the standard deviation is 3.822448314.
Approx 0.55
mean | 30 median | 18 standard deviation | 35.496
The standard deviation, in itself, cannot be high nor low. If the same measurements were recorded using a unit that was a ten times as large (centimetres instead of millimetres), the standard deviation for exactly the same data set would be 1.8. And if they were recorded in metres the sd would be 0.018
√2.5
3.6
The numbers posted are multiples of 3. In the question, you will find that if you look closely, you can find that some of the numbers are 2 numbers away from the original number
64.
The formula for the standard deviation of a sample (s) is given by: s =√(⅟₍n₌₁₎Σ(y-ȳ)²) where y are the data points and ȳ is their mean; it can be rearranged to give: s = √(⅟₍n₌₁₎(Σy² - n((Σy)/n)²) → s = √(⅟₍₅₌₁₎(1815 - 5(⁹⁵/₅)²) → s = √(¼ × 10) → s = √2.5