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This sequence can be generalized as: 1+10^-(n+2) where n = 0,1,2,3,.... As n goes to infinity, 10^(-inf) goes to zero. So, the final term in the sequence will be 1.

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1.00001

Q: How do you finish the sequence 1.01 1.001 1.0001?

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10^n+1

Written as a binary number, 10 + 101 + 1010 = 10001.

Binary sum 1001+101+11 = 10001Recall:0 + 0 = 00 + 1 = 01 + 0 = 01 + 1 = 10Start from the end:1 + 1 + 1 = 1 carry on 11 + 1 + 0 + 0 = 0 carry on 11 + 1 + 0 = 0 carry on 11 + 1 = 10or1001 = 23 + 20 = 8 + 1 = 9101 = 22 + 20 = 4 + 1 = 511 = 21 + 20 = 2 + 1 = 317 = 24 + 20 = 10001

32.

1. 1 2. 10 3. 11 4. 100 5. 101 6. 110 7. 111 8. 1000 9. 1001 10. 1010 11. 1011 12. 1100 13. 1101 14. 1110 15. 1111 16. 10000 17. 10001 18. 10010 19. 10011 20. 10100

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10^n+1

echo "1 101 1010 10001";

122

Written as a binary number, 10 + 101 + 1010 = 10001.

1/101 is then added, the result is 10001/999900

1110

10.1

in binary 10=2 101 =5 1010 = 10 2+5+10 =17 17 =10001 in binary 10001 is answer ^^

10001 (binary code system)

101 is not a number sequence. So the question, as stated, makes no sense.

Doen't anybody care that the binary numbers at the head of the page is incorrect? There is no 11, although the answer below is correct. 1 10 11 100 101 110 111 1000 1001 1010 1011 1100 1101 1110 1111 10000 10001 10010 10011 10100

100 1000 100 0001 101 0110 100 0101 100 0001 100 1110 100 1001 100 0011 100 0101 100 0100 100 0001 101 1001---------Binary Representation. 110 101 126 105 101 116 111 103 105 104 101 131.------Octal