33 x 33/3 = 33 x 11 = 363
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
Such that the square root of 363 is equal to 19.05256 (rounded to five decimal places), the square root of -363 is euqal to 19.05256 i. The lower-case letter i represents the square root of minus one, an imaginary number.
33 + (3 + 3)/3
The factors of 363 are: 1, 3, 11, 33, 121, 363
3^3 - (3 x 3 x 3) is zero.
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
The prime factorization of 363 is 3x112.
It is 5.333... (3s repeating).
3x7+4x2
Such that the square root of 363 is equal to 19.05256 (rounded to five decimal places), the square root of -363 is euqal to 19.05256 i. The lower-case letter i represents the square root of minus one, an imaginary number.
There are one 3s orbital, three 3p orbitals, and five 3d sublevels.
To get 100 using eight 3s, you can use the following expression: ( (3 + 3) \times (3 + 3) + (3 + 3) ). This simplifies to ( 6 \times 6 + 6 = 36 + 6 = 100 ). Thus, by creatively combining the 3s, you can achieve the desired result.
33/3 = 11
(3 + 3) / .3
96/3=32... without using a calculator !
33 + (3 + 3)/3
26% of 363= 26% * 363= 0.26 * 363= 94.38