The easiest way is to use Archimedes principle ! Immerse the object in a container of water that is full to the brim - then collect the displaced over-spill, and measure it.
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He discovered the method to calculate the volume of a irregular object (rock).
by a graduated cylinder (don't rely on this answer i am not sure of it)
One way to figure this out is to put the object in a graduated cylinder containing water and measuring the changes in the volume of the water.
By definition, an irregular object is one that does not have an easy mathematical representation, it is extremely difficult (if not impossible) to calculate its volume without placing it into a solution of some sort. Attempts to calculate volume otherwise would be subject to severe rounding error, and would thus make it unsuitable for scientific use. For the very special case where the object is uniform and/or its density, ρ=m/V, is known, then its volume could be determined from its mass, V=m/ρ.
millilitre or litre - depending on size. Or possibly microlitre, kilolitre, megalitre etc.