Put x = 0 (cover up the x term).
You are left with -8y = 16 and dividing by -8 gives y = -2
So (0, -2) is one point on the line.
Put y = 0 (cover up the y term).
You are left with -2x = 16 and dividing by -2 gives x = -8
So (-8, 0) is another point on the line.
Join the two ponits and extend the line as required.
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3x - 8y + 2x - 5 - 5y = 5x -13y - 5
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
12x-8y
-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4
Solve by the substitution method the given system of the linear equations of 3 variables.2x + 7z = 648y + 6z = 403x - 2y + 4z = 46 (add the first equation with the second equation)2x + 8y + 13z = 1043x - 2y + 4z = 46 (multiply the second equation by 4)2x + 8y + 13z = 10412x - 8y + 16z = 184 (add both equations)14x + 29z = 28814x + 29z = 2882x + 7z = 64 (multiply the second equation by -7)14x + 29z = 288-14x - 49z = -448 (add both equations)-20z = -160 (divide both sides by -20)z = 82x + 7z = 64 (substitute 8 for z)2x + 7(8) = 642x + 56 = 64 (subtract 56 to both sides)2x = 8(divide by 2 to both sides)x = 48y + 6z = 40 (substitute 8 for z)8y + 6(8) = 408y + 48 = 40 (subtract 48 to both sides)8y = -8 (divide by 8 to both sides)y= -1Thus, the solutions are x = 4, y = -1, and z = 8.