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4 is a constant, so you can pull it out of the integral. Use a u substitution with u = 3-x and du = -dx. If it's a definite integral, remember to change the limits of integration. The integral is then simply 1/u which integrates to be ln u. Substitute back in 3-x for u and you have the answer to be: -4*ln (3-x) + C
What else can I help you with?
What is 2 over 3x equals 4?
"2 over 3x equals 4" is an equation in a single variable, x.2/(3x) = 4 => 3x/2 = 1/4 => 3x = 2/4 = 1/2 => x = 1/6.
What is the answer to 4 equals 3x-14?
4=3x-14 18=3x I carried the 14 over and it became positive. x=6 I divided 18 by 3.
What is the answer to 3x over 4 minus 5 equals x over 3 plus 10?
If: 3x/4 -5 = x/3 +10 Then: x = 36
How do you do (3x 4)2?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
What is x squared minus10 over x squared minus 4 plus 3x over x squared minus 4?
For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2
Why is 3x over 4 plus x equal to 7x over 4?
3x/4 + x = 7x/4 because 4x/4 = x 3x/4 + 4x/4 = 7x/4
What is 2 over 3x equals 4?
"2 over 3x equals 4" is an equation in a single variable, x.2/(3x) = 4 => 3x/2 = 1/4 => 3x = 2/4 = 1/2 => x = 1/6.
How do you Differentiate and Integrate y equals 3x?
dy/dx = 3 integral = (3x^2)/2
3X-4 all over 1- 2X-4?
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
What is the answer to 4 equals 3x-14?
4=3x-14 18=3x I carried the 14 over and it became positive. x=6 I divided 18 by 3.
What is the answer to 3x over 4 minus 5 equals x over 3 plus 10?
If: 3x/4 -5 = x/3 +10 Then: x = 36
What is f0 equals 3x-4 over 5?
f(x) = (3x - 4)/5 f(0) = [3(0) - 4]/5 = -4/5
How do you do (3x 4)2?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
What is the indefinite answer of 3(3x-1)4 dx?
To find the indefinite integral of the expression (3(3x-1)^4 , dx), we can use the power rule of integration. First, we can factor out the constant 3, then apply the substitution method or directly integrate. The integral becomes: [ \int 3(3x-1)^4 , dx = 3 \cdot \frac{(3x-1)^5}{15} + C = \frac{(3x-1)^5}{5} + C, ] where (C) is the constant of integration.
How do you distribute 3x(x-4)?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
Are 3x-y equals 4 and y equals 3x-4 equivalent to each other?
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
What is x squared minus10 over x squared minus 4 plus 3x over x squared minus 4?
For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2
