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so the problem is

∫(sin7x)dx

you have to use u-substitution,

set u=7x

then du/dx=7 so du=7dx and solve for dx 1/7du=dx,

so you get

1/7∫(sinu)du then integrate like normal, and you get

1/7(-cosu)+C then you plug u back in and get 1/7(-cos7x)+C

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Q: How do you integrate sin7x?
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