Do it by parts. Int(u.dv) = u.v - int(v.du)
Let x = u, then dx = du. Let e^x = dv, then v = e^x.
Plug into formula: xe^x - int(e^x.dx)
= x.e^x - e^x or e^x(x-1)+C
Chat with our AI personalities
5/5x + c where c is the constant of intergration just differentiate the 5x to get 5 and times that by 1/5x then add c The answer above is wrong. This is simply because you cannot intergrate lnx to get 1/x. To intergrate I would recommend using intergration by parts. u=ln5x du/dx=1/x dv/dx=1 v=x uv-(intergal of)v.du/dx =xln5x-intergral of x/x intergral of x/x = x =xln5x-x+c = x(ln5x-1)+c
x
X to the fourth power is... X times X times X times X
By definition of powers, x to the power y = x*x*x*........y times x to the power 1 = x Therefore, 10 to the power 1 = 10.
When multiplying two terms with the same base, you add the exponents. In this case, x to the fifth power times x to the third power would be x to the power of 5 + 3, which simplifies to x to the power of 8. So, x to the fifth power times x to the third power equals x to the eighth power.