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5/5x + c where c is the constant of intergration
just differentiate the 5x to get 5 and times that by 1/5x then add c
The answer above is wrong. This is simply because you cannot intergrate lnx to get 1/x. To intergrate I would recommend using intergration by parts.
u=ln5x du/dx=1/x dv/dx=1 v=x
uv-(intergal of)v.du/dx
=xln5x-intergral of x/x intergral of x/x = x
=xln5x-x+c = x(ln5x-1)+c
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Integration of x ln 5x dx?
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