Well, darling, to calculate log base 2 on your TI-86 calculator, you simply press the "LOG" button, then type in "2" and hit enter. Voila! You've got your answer. Now go forth and conquer those logarithms like the math boss you are.
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Be careful . On calculatoirs there are TWO logarithm bases, indicated by 'log' and 'ln'.
They are not interchangeable.
'log' is logs to base '10'
'ln' is logs to the 'natural' base ; natural = 2.718281828....
Try 'log' , 'number'. '=' and the answer should appear.
e.g. log(4) = 0.6020599999....
ln(4) = 1.386294371....
Note the two different answers.
Notwithstanding, what is written above, by a special higher level mathemtics , log bases can be changed. However, whilst learning logarithms, keep to 'base 10' ( log).
Oh, dude, it's like super easy. So, you just hit the "log" button on your TI-86 calculator, then type in 2, and boom, there you have it - log 2. It's like magic, but not really. Just don't forget to carry the 1 or whatever.
To key in log base 2 on a TI-86 calculator, you would typically use the "log" function with a base specified. On the TI-86, you can input log base 2 as log(2,2). This tells the calculator to calculate the logarithm of 2 with a base of 2. Simply input this into the calculator and press enter to get the result.
When doing the log of a base other than 10 or e you put the numbers in as if you were doing a log either of those bases and then divide the answer by log or ln of the base number you want.
Ex.
Log 3 (17)
You enter: log(17) / log(3)
or
ln(17) / ln(3)
The anti-log is "10^x" listed above the "LOG" key on a TI-86 calculator. All you have to do to use it is press the yellow "2nd" key (this means shift) and then press the "LOG" key.
To find anti log of a number enter the number as the exponent of 10.
Yes it is hidden you need to hit the green (Diamond) and press 7.
Texas Instruments TI-30xIIS calculator?
If you are trying do logba, there are three ways of doing it.Update to OS 2.53Install the Omnicalc App (don't update to OS 2.53, Omnicalc will conflict)Use the change of base formula. log(a)/log(b)