when you write simple parabole eqn. y = x^2 it means when y = 9 x = -3 and x = +3 i.e x takes 2 values for one y.
So graph has to open up. why "up" beacause eqn is for positive y.
If you know the equation, you just plug in x = 0 and solve.
right apex. hope that helps
-2
Solution 1Start by putting the parabola's equation into the form y = ax2 + bx + c if it opens up or down,or x = ay2 + by + c if it is opens to the left or right,where a, b, and c are constants.The x-value for the vertex is -(b/2a). You can use this x-value to solve for the y-value by substituting the x value in the original quadratic equation.Solution 2Put the parabola's equation into this form: y - k = 4p(x - h)2or x - h = 4p(y - k)2You just need to simplify the equation until it looks like this. The vertex is located at the coordinates (h,k). (p is for the focus, but that isn't important as long as you know h and k.)
Did you mean the slope of a line/parabola/etc.? A slope, in its simplest terms, is how much a line angles away from the horizontal. It describes the steepness, sense, and incline of a line.Finding the slope of a line requires two distinct point ON a line. It's given by the equation: a = (y2 - y1) / (x2 - x1) where a is the slope, (x1,y1) are the coordinates of the first point, and (x2,y2) the coordinates of the second point. An equation for a straight line is usually represented as y = a*x + b; you could extract the slope by simply looking at the given values of a (the slope).Finding the slope of a curve (parabola, etc.) is taken at the tangent point. As you move along the curve, the slope changes (i.e the slope is NOT constant). The slope of a curve can be found by taking the derivative of the function that defines the curve. After derivation, you just plug in the values of x at where you want to find the slope at.
No, a parabola is the whole curve, not just a part of it.
If you know the equation, you just plug in x = 0 and solve.
If you have the equation in the form y = ax^2 + bx + c (where "^2" means squared), if "a" is positive, the parabola opens upwards; otherwise it opens downwards.
right apex. hope that helps
-2
A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right. It's not just the '4' that is important, it's '4a' that matters. This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable. For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)
To have a parabola with only one x-intercept, the vertex of the parabola must lie on the x-axis. This means the parabola opens either upwards or downwards, depending on the coefficient of the squared term in the equation. If the coefficient is positive, the parabola opens upwards, and if it is negative, the parabola opens downwards. By adjusting the coefficients in the equation of the parabola, you can position the vertex such that there is only one x-intercept.
No. A linear equation is just one type of function.If you graph a linear equation, you get a straight line.A "function" on the other hand can take on many different forms: a straight line, a wave line (the sine function), a parabola, etc.No. A linear equation is just one type of function.If you graph a linear equation, you get a straight line.A "function" on the other hand can take on many different forms: a straight line, a wave line (the sine function), a parabola, etc.No. A linear equation is just one type of function.If you graph a linear equation, you get a straight line.A "function" on the other hand can take on many different forms: a straight line, a wave line (the sine function), a parabola, etc.No. A linear equation is just one type of function.If you graph a linear equation, you get a straight line.A "function" on the other hand can take on many different forms: a straight line, a wave line (the sine function), a parabola, etc.
A quadratic equation always has 2 solutions.In the instance of perfect squares, however, there will be just one number, which is a double root. Graphically, this is equivalent of the vertex of a parabola just barely touching the x-axis.
If each side of the equation is a fraction, then it is a proportion.
You can tell by the presence or absence of a negative number for a in the form ax2+bx+c. So, for example, 4x2+2x+1 opens upwards, while -4x2+2x+1 opens downwards.
Solution 1Start by putting the parabola's equation into the form y = ax2 + bx + c if it opens up or down,or x = ay2 + by + c if it is opens to the left or right,where a, b, and c are constants.The x-value for the vertex is -(b/2a). You can use this x-value to solve for the y-value by substituting the x value in the original quadratic equation.Solution 2Put the parabola's equation into this form: y - k = 4p(x - h)2or x - h = 4p(y - k)2You just need to simplify the equation until it looks like this. The vertex is located at the coordinates (h,k). (p is for the focus, but that isn't important as long as you know h and k.)