The multiples of a whole number are found by taking the product of any counting number and that whole number. For example, to find the multiples of 5, multiply 5 by 1, 5 by 2, 5 by 3, and so on. The multiples are the products of these multiplications.
To find out if a number is a multiple of another, simply reverse the process and divide by 5.
115 divided by 5 is 23 so 115 is a multiple of 5
Yes - any number ending in 5 or 0 is a multiple of 5.
To find the least common multiple (LCM) of 55, 75, and 115, we first need to factorize each number into its prime factors. The prime factorization of 55 is 5 x 11, 75 is 3 x 5 x 5, and 115 is 5 x 23. The LCM is the product of the highest power of all prime factors present in the factorization of each number. Therefore, the LCM of 55, 75, and 115 is 3 x 5 x 5 x 11 x 23 = 8625.
115 = 5 x 23
-110
Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
Yes. Any number than ends in a 0 or a 5 is a multiple of 5.
Multiple of 5 before 115 is 110.
Yes - any number ending in 5 or 0 is a multiple of 5.
The least common multiple of 23 and 5 is 115
115 is.
The Least Common Multiple (LCM) for 23 5 is 115.
If that's 23 and 5, any multiple of 115. If that's 2, 3 and 5, any multiple of 30.
Any number ending in a 5 or a 0 is a multiple of 5. So... a three digit multiple could be : 100, 105, 110, 115.........995
Their least common multiple (or their product - any multiple will do), and any multiple of that.
23, 46, 69, 92, 115, 138, 161, 184, 207, 230, 253, . . .
The LCM (Least Common Multiple) of 115 and 15 is 345. The prime factors of 115 are 5 and 23. The prime factors of 15 are 3 and 5. Multiply the smallest encountered number of same factors, 3, 5, and 23, to get 345.
The Least Common Multiple (LCM) for 70 115 is 1,610.