Yes - any number ending in 5 or 0 is a multiple of 5.
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To find the least common multiple (LCM) of 55, 75, and 115, we first need to factorize each number into its prime factors. The prime factorization of 55 is 5 x 11, 75 is 3 x 5 x 5, and 115 is 5 x 23. The LCM is the product of the highest power of all prime factors present in the factorization of each number. Therefore, the LCM of 55, 75, and 115 is 3 x 5 x 5 x 11 x 23 = 8625.
The multiples of a whole number are found by taking the product of any counting number and that whole number. For example, to find the multiples of 5, multiply 5 by 1, 5 by 2, 5 by 3, and so on. The multiples are the products of these multiplications.To find out if a number is a multiple of another, simply reverse the process and divide by 5.115 divided by 5 is 23 so 115 is a multiple of 5
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Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
To calculate how many times 5 goes into 115, you would perform division. 115 divided by 5 equals 23. Therefore, 5 goes into 115 a total of 23 times.