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Davida has 83 coins in nickels and dimes she has a total of 6.95 How many of each coin dose she have?
There are 83 coins. If there are N nickels then there are (83 - N) dimes. Davida has nickels worth 5N and dimes worth 10(83 - N) but. 5N + 10(83 - N) = 695 5N + 830 - 10N = 695 5N = 830 -695 = 135 therefore N = 135/5 = 27 : D = 83 - N = 83 - 27 = 56 Davida has 27 nickels and 56 dimes.
Anna has 15 coins in her purse. All are nickels and dimes. They total 1.35?
D + N = 15, so D = 15 - N; 10D + 5N = 135. Substitute: 10(15 - N) + 5N = 135 ie 150 - 10N + 5N = 135 ie 5N = 15 So she has 3 nickels and 12 dimes (3 x 5) + (12 x 10) = 15 + 120 = 135 QED
How do you write 13.5 cents?
$.135 or 13.5¢
Examples of coin problem with solution?
Eugenia had five times as many quarters as dimes. If the total value of her coins was $16.20 how many of each kind of coin did she have?Let x= the amount of dimes Eugenia had (dimes are worth 10)Let 5x= the amount of quarters Eugenia had (quarters are worth 25)Equation: 10(x) + 25(5x)=1620 (because that is how many cents there are)10(x)+25(5x)=162010x+125x=1620135x=16201/135(135)=1/135(1620)1x= 12x=12check10(x) + 25(5x)=162010(12)+25(5x12)=1620120+25(60)=1620120+1500=16201620=1620x=125x=1500Therefore Eugenia had 12 dimes and 60 quarters
What fraction of 2 dollars is 27 cents?
135/1000 or 27/200
Davida has 83 coins in nickels and dimes she has a total of 6.95 How many of each coin dose she have?
There are 83 coins. If there are N nickels then there are (83 - N) dimes. Davida has nickels worth 5N and dimes worth 10(83 - N) but. 5N + 10(83 - N) = 695 5N + 830 - 10N = 695 5N = 830 -695 = 135 therefore N = 135/5 = 27 : D = 83 - N = 83 - 27 = 56 Davida has 27 nickels and 56 dimes.
Anna has 15 coins in her purse. All are nickels and dimes. They total 1.35?
D + N = 15, so D = 15 - N; 10D + 5N = 135. Substitute: 10(15 - N) + 5N = 135 ie 150 - 10N + 5N = 135 ie 5N = 15 So she has 3 nickels and 12 dimes (3 x 5) + (12 x 10) = 15 + 120 = 135 QED
How do you write 13.5 cents?
$.135 or 13.5¢
Examples of coin problem with solution?
Eugenia had five times as many quarters as dimes. If the total value of her coins was $16.20 how many of each kind of coin did she have?Let x= the amount of dimes Eugenia had (dimes are worth 10)Let 5x= the amount of quarters Eugenia had (quarters are worth 25)Equation: 10(x) + 25(5x)=1620 (because that is how many cents there are)10(x)+25(5x)=162010x+125x=1620135x=16201/135(135)=1/135(1620)1x= 12x=12check10(x) + 25(5x)=162010(12)+25(5x12)=1620120+25(60)=1620120+1500=16201620=1620x=125x=1500Therefore Eugenia had 12 dimes and 60 quarters
How tall is a stack of 100 dimes?
about 10cm because 1 dime=1mm* * * * *That would be OK if a dime was 1 mm but it isn't. It is 1.35 mm so that a stack of 100 is 135 mm = 13.5 cm.
What fraction of 2 dollars is 27 cents?
135/1000 or 27/200
72 coins nickels and dimes equal 4.95?
This is a simultaneous-equation problem. Because there are two variables - the number of nickels and the number of dimes - we have to set up two relationships between them in order to solve the system.Let n be the number of nickels and d be the number of dimes.Because there's a total of 72 coins, the first equation is n + d = 72.The second thing we know is that the total value is $4.95. It's easiest to express each amount in cents, n nickels are worth 5n cents, d dimes are worth 10d cents, and $4.95 is 495 cents so the second equation is 5n + 10d = 495.From here there are two ways to obtain the answer.Method 1 - SubstitutionBecause the first equation is n + d = 72, we can express n in terms of n as n = 72 - d.Then replace the "n" term of the second equation with the new expression in terms of d: 5(72 - d) + 10d = 495Expanding the left side gives 5*72 - 5d + 10d = 495.Next collect like terms: 360 + 5d = 495Finally solve for d: 5d = 495 - 360, or 5d = 135so d = 135/5, or d = 27; i.e. there are 27 dimes.Because we know there are 72 coins in total (d + n = 72) there must be 45 nickels.Method 2 - BalancingWrite the equations on two successive lines: n + d = 725n + 10d = 495The coefficient of n in the first equation is 1 (implied) and the coefficient in the second equation is 5 (explicit). To balance the two, multiply every term in the first equation by 5 so the "n" term has the same coefficient in both: 5n + 5d = 3605n + 10d = 495Both equations now share a "5n" term. The "d" coefficient is larger in the second equation so subtract the first equation from the second: 5n + 10d = 495-[5n + 5d = 360]------------------------or (5n - 5n) + (10d - 5d) = 495 - 360The 5n and -5n terms cancel each other out, leaving 5d = 135, or d = 27 and n = 45, the same answer as in Method 1 (which it should be!!) Check: 27 dimes are worth 27*10 = $2.70. 45 nickels are worth 45*5 = $2.25. The total value is $4.95.
How do you make 135 percent a decimal?
To convert 135% to decimal divide by 100: 135% ÷ 100 = 1.35
How much is a 1904 Liberty Head nickel?
Poor Condition -- 2.50$ Great Condition -- [CAN get up to] 135$ Face Value -- 0.05 USD Numismatic Value -- 2.50$ to 135$ In 1817, proof Liberty Head nickels were issued and were worth around 300$
What two numbers are times together to make 135?
They can be: 27 times 5 = 135
What 4 primes make 135?
As a product of its prime factors: 3*3*3*5 = 135
What 4 numbers multiply to make 135?
3 x 3 x 3 x 5 = 135
