A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
(4 + 4 + 4) ÷ 4 = 12 ÷ 4 = 3.
11 = 4/.4 + 4/4
it is not posible *Ahem*. 4*4+4/sqrt(4)
you can not
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
(4+4)/4 + 4
4 × ((4 ÷ 4) + 4)=20
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
There are six fours in twenty-four.
One way to use four fours to make 25 is 4 + 4 + 4 + √4, which equals 25.
(4 + 4 + 4) ÷ 4 = 12 ÷ 4 = 3.
4+4-(4/4)=7
11 = 4/.4 + 4/4
4 + 4 + (4/4) = 9
fourteen take away four and then add a four and times by (2 times 4)