First, find two numbers that when multiplied together equal 189.
I can tell by looking at the number that it is divisible by 9. Any number whose digits add up to a number divisible by 9 is also divisible by 9. 1 + 8 + 9 = 18, which is divisible by 9. 189 ÷ 9 is 21.
So, the top of our factor tree is:
189
9 x 21
Now, determine two pairs of numbers that when multiplied together, one pair will equal 9 and the other pair will equal 21. 9 = 3 x 3 and 21 = 7 x 3.
So, now our factor tree is:
189
9 x 21
(3x3) x (7x3)
You would continue doing this until you no more numbers can be factored. Since 3 and 7 are prime numbers, the factor tree is finished.
The factor tree shows that the prime factorization of 189 is 3 x 3 x 3 x 7 or 33 x 7.
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15,3 3,5,3
The GCF of 189, 315, and 441 is: 63
27 3,9 3,3,3
9x9=81. Proving that one of the factor trees for 81 is 9xp.
441 / 252 = 1 r 189 252 / 189 = 1 r 63 189 / 63 = 3 r 0 The hcf of 441 and 252 is 63