252
28 x 9
7 x 4 x 3 x 3
7 x 2 x 2 x 3 x 3
or
252
12 x 21
3 x 4 x 7 x 3
3 x 2 x 2 x 7 x 3
or
252
14 x 42
7 x 2 x 21 x 2
7 x 2 x 7 x 3 x 2
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
15,3 3,5,3
27 3,9 3,3,3
9x9=81. Proving that one of the factor trees for 81 is 9xp.
441 / 252 = 1 r 189 252 / 189 = 1 r 63 189 / 63 = 3 r 0 The hcf of 441 and 252 is 63
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
252 126,2 63,2,2 21,3,2,2 7,3,3,2,2
252 2x126 2x2x63 2x2x3x3x7
It is: 22*32*7 = 252
252 Divide by two. 126,2 Divide by two. 63,2,2 Divide by three. 21,3,2,2 Divide by three. 7,3,3,2,2 Stop. All the factors are prime.
No, 2 is a factor of 252. 252 is a multiple of 2.
We note that 504 is a even number, because it ends in ;4; which is an even number. Hence we divide 504 by '2' which is the lowest prime number and an even numbers. Keep on dividing by '2' until the answer is no longer even, Then try '3' , then'5' and continue with prime numbers. Hence again 2)504 2)252 2)126 63 '63' is NOT an even number , so try '3' which is the next prime number. Hence 3)63 3)21 7)7 =1 Keep dividing by prime number until the system is reduced to '1'. So all the factors of 504 are 2,2,2,3,3,& 7. You can combine(multiply) any pair or more of these factors, and they will all be part of the factor tree of 504. Hence 2 ) 2 x 1) 4, ( 2 x 2) 6 ( 2 x 3) 8 ( 2x2x2) 9 ( 3 x 3 ) 12 (2x2x3 = 4 x 3) 14 ( 2 x 7 _ 18 ( 2 x 3 x 3 = 2 x 9 ) 21 ( 3 x 7 ) 24 ( 2 x 2 x 2 x 3 = 8 x 3) 28 ( 2 x 2 x 7 = 4 x 7) 36 ( 2 x 2 x 3 x 4 = 4 x 9 ) 56 (21 ( 2 x 2 x 2 x 7 = 8 x 7 ) 63 ( 3 x 3 x 7) 72 ( 2 x 2 x 2 x 3 x 3 = 8 x 9 ) The full factor tree of 504 . , with their factors.
The greatest common factor of 252 and 300 is 12.
No because its largest even factor is itself 252