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Complex analysis is a metric space so neighborhoods can be described as open balls. Proof follows

a. Assume that the set has an accumulation point call it P.

b. An accumulation point is defined as a point in which every neighborhood (open ball) around P contains a point in the set other than P.

c. Since P is an accumulation point, I can choose an open ball around P that has a diameter less than the minimum distance between P and all elements of the finite set. Therefore there exists a neighbor hood around P which contains only P. Therefore P is not an accumulation point.

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Q: How do you prove that a finite set of points cannot have any accumulation points in a complex analysis?
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