If you have a finite set of points (call them A1, A2, A3...), then you have a finite set of distances to the points.
So for any point B, simply pick a distance D that's smaller than the distance between B and A1, the distance between B and A2, and so on. (This is possible, since there a finite number of points.)
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Since there are no points within distance D of B (because this is how you chose D), point B can not be an accumulation point (because an accumulation point must have points within any given distance of it)
Complex analysis is a metric space so neighborhoods can be described as open balls. Proof follows a. Assume that the set has an accumulation point call it P. b. An accumulation point is defined as a point in which every neighborhood (open ball) around P contains a point in the set other than P. c. Since P is an accumulation point, I can choose an open ball around P that has a diameter less than the minimum distance between P and all elements of the finite set. Therefore there exists a neighbor hood around P which contains only P. Therefore P is not an accumulation point.
A discrete graph.
Let's think of a line segment as a finite set of points. Along those lines, (pun intended) think of a ray and a line as infinite sets of points. Then we think of longer in terms of the size of the set. So for example, a 2 inch line segment would be longer than a 1 inch line segment because we can have more points in the set which is made of the two inch segment. The ray and the line are the same size since they both can be viewed as sets containing an infinite number of points. The line segment being a finite set is smaller than the other two.
A circle cannot have end points!
The expression in the question contains two decimal points and so cannot be a number.
Complex analysis is a metric space so neighborhoods can be described as open balls. Proof follows a. Assume that the set has an accumulation point call it P. b. An accumulation point is defined as a point in which every neighborhood (open ball) around P contains a point in the set other than P. c. Since P is an accumulation point, I can choose an open ball around P that has a diameter less than the minimum distance between P and all elements of the finite set. Therefore there exists a neighbor hood around P which contains only P. Therefore P is not an accumulation point.
No, not all adherent points are accumulation points. But all accumulation points are adherent points.
Finite element analysis is used to evaluate materials to determine their performance under particular stresses, in order to determine weak points in a structure. There are FEA software programs available to record the calculations, but performing the analysis correctly may require training in mechanical engineering.
In finite element analysis, a field variable represents a physical quantity that varies over the domain of the finite element mesh. Examples include displacement, temperature, stress, and strain. Field variables are computed at specific points within each element and are used to describe the behavior of the system being analyzed.
This is called a discrete set (all points isolated) or a finite set. Finite sets are always discrete.
Infinite.
Yes, every point in an open set is an accumulation point.
No.
Yes
true
Deflection on a structure can be calculated using structural analysis methods such as the moment-area method, virtual work method, or finite element analysis. These methods involve determining the forces acting on the structure and applying principles of equilibrium to calculate the deflections at various points. The specific method chosen depends on the complexity of the structure and the accuracy required for the analysis.
A discrete graph.