Draw the line x = -1 which is a vertical line (parallel to the y-axis) that goes through (-1 , 0)
Shade the side to the left of it as those numbers are less than -1.
use a line graph. Place a solid dot at 4. Shade the entire region to the left of 4.x is Less than shade Left.* * * * * The above answer is so very wrong - it has missed out the key word "absolute".Use a line graph. Put a solid dot at -4 and another solid dot at +4 and join them. Every point on the line (including the two end points) is the graph.
if you have y <= f(x), then graph the function y = f(x) with a solid line, then shade everything below that graph.
If the inequality is strict (< or >) then the boundary is not included. Otherwise (≤ or ≥), it is.
y >= -3 + xThis is the same asy>= x-3Start off by sketching the regular graph of y=x-3 (should look the same as the graph of y=x but shifted down 3 places so that the y intercept is at the point (0,-3)).Now just shade the half of the graph where y is greater (so shade in the positive direction for y above the graph of the line).In the end you should have the graph of a diagonal line shaded over the top.***Note: You will draw your graph with a solid line because because the question says GREATER THAN OR EQUAL TO. If you ever get a graph that is strictly greater than or strictly less than, instead of drawing a solid line, draw a dotted line, to show that you're not including the values where y is equal to your function.If you get y> shade in the positive y direction and use a dotted line.................y< shade in the negative y direction and use a dotted line.................y>= shade in the positive y direction and use a solid line.................y
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If the graph is a two-dimensional plane and you are graphing an inequality, the "greater than or equal to" part will be shown by two things: (1) a solid, not a dotted, line--this part signifies the "or equal to" option--and (2) which region you shade. Shade the region that contains the points that make the inequality true. By shading that region, you are demonstrating the "greater than" part.
use a line graph. Place a solid dot at 4. Shade the entire region to the left of 4.x is Less than shade Left.* * * * * The above answer is so very wrong - it has missed out the key word "absolute".Use a line graph. Put a solid dot at -4 and another solid dot at +4 and join them. Every point on the line (including the two end points) is the graph.
In a plane, it is the area to the left of the vertical line through x = -1. Since it is not a strict inequality, the line should be drawn solid (not dashed or dotted).
if you have y <= f(x), then graph the function y = f(x) with a solid line, then shade everything below that graph.
If the inequality is strict (< or >) then the boundary is not included. Otherwise (≤ or ≥), it is.
To graph linear inequalities involving two variables, first, rewrite the inequality in slope-intercept form (y = mx + b) if necessary. Next, graph the corresponding linear equation as if it were an equality (using a solid line for ≤ or ≥ and a dashed line for < or >). Finally, shade the appropriate region of the graph: above the line for greater than or greater than or equal to, and below the line for less than or less than or equal to. This shaded area represents all the possible solutions to the inequality.
To graph the equation (-2 \leq 2x - 44), first, you can rearrange it to isolate (x): add 44 to both sides to get (42 \leq 2x), then divide by 2, giving (21 \leq x) or (x \geq 21). This represents a vertical line at (x = 21) on the graph, with a solid line indicating that (x) can equal 21. Shade the region to the right of this line to show all values of (x) that satisfy the inequality.
To determine the solution region for a system of inequalities, first graph each inequality on the same coordinate plane. For linear inequalities, use a dashed line for "less than" or "greater than" and a solid line for "less than or equal to" or "greater than or equal to." Shade the region that satisfies each inequality; the solution region is where all shaded areas overlap. This overlapping area represents all the points that satisfy all inequalities in the system.
To graph a two-variable linear inequality, first convert the inequality into an equation by replacing the inequality sign with an equal sign, which gives you the boundary line. Next, graph this line using a solid line for ≤ or ≥ and a dashed line for < or >. Then, determine which side of the line to shade by testing a point not on the line (usually the origin) to see if it satisfies the inequality. Finally, shade the appropriate region to represent all the solutions to the inequality.
y >= -3 + xThis is the same asy>= x-3Start off by sketching the regular graph of y=x-3 (should look the same as the graph of y=x but shifted down 3 places so that the y intercept is at the point (0,-3)).Now just shade the half of the graph where y is greater (so shade in the positive direction for y above the graph of the line).In the end you should have the graph of a diagonal line shaded over the top.***Note: You will draw your graph with a solid line because because the question says GREATER THAN OR EQUAL TO. If you ever get a graph that is strictly greater than or strictly less than, instead of drawing a solid line, draw a dotted line, to show that you're not including the values where y is equal to your function.If you get y> shade in the positive y direction and use a dotted line.................y< shade in the negative y direction and use a dotted line.................y>= shade in the positive y direction and use a solid line.................y
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If you mean with inequalities: 1. Change the inequality into an equation.2. Solve the equation for the initial line.3. Look back to the inequality.a.) greater than or equal to-shade above or to the left of your line,this line should be solidb.) greater than-shade above or to the left of your line,this line should not be solidc.) less than or equal to-shade below or to the right of your line,this line should be solidd.) less than-shade below or to the right of your line,this line should not be solidHope this helps.