If the inequality is strict (< or >) then the boundary is not included. Otherwise (≤ or ≥), it is.
Substitute the number in place of the variable, and see whether the inequality is then a true statement.
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
A parenthesis is used for a number which is an 'end' of an inequality but is not itself included. For example, if the inequality reads "x>3", there is an opening parenthesis on the hash-mark labelled '3', and the number line is shaded to the right. If the number IS included a bracket is used. So for -3 is less than or equal to x but less than 3, there is a [ on -3, and a ) on the 3, and the number line is shaded between -3 and 3.
A dashed line is used when the equality is equal to and less than/more than. (≤, ≥) A solid line is used when the inequality is just less than/more than. (<, >)
It depends upon whether the inequality is strictly less than (<), or if it is less than or could be equal (≤). For example: if x < 6, x can have any value less than 6, but cannot have the value 6; but if x ≤ 6, x can have any value less than 6, but can also have the value 6. Or put another way, x = 6 is NOT a solution of x < 6, but IS a solution to x ≤ 6.
Substitute the number in place of 'x' in the inequality, and see whether the statement you have then is true.
When graphing a linear inequality, the first step is to replace the inequality symbol with an equal sign to graph the corresponding linear equation. This creates a boundary line, which can be solid (for ≤ or ≥) or dashed (for < or >) depending on whether the points on the line are included in the solution set. After graphing the line, you then determine which side of the line represents the solution set by testing a point (usually the origin if it's not on the line) to see if it satisfies the original inequality. Finally, shade the appropriate region to indicate the solutions to the inequality.
Substitute the number in place of the variable, and see whether the inequality is then a true statement.
That will all depend on what the question was!
To graph linear inequalities, you first identify the boundary line by rewriting the inequality in slope-intercept form (y = mx + b) and plotting the corresponding linear equation. If the inequality is strict (e.g., < or >), you use a dashed line to indicate that points on the line are not included. For non-strict inequalities (e.g., ≤ or ≥), a solid line is used. Finally, you shade the appropriate region of the graph to represent the solutions that satisfy the inequality, based on whether the inequality is greater than or less than.
The answer depends on the nature of the inequality: whether it is linear, quadratic or has some other functional form.
Whether inequality exist
If the inequality is > or< then it is an open circle. If it is greater than or equal to or less than or equal to, it is a closed circle.
I don't see any numbers below.One method to solve this is to replace each of the numbers in the inequality, do the calculations, and then check whether the inequality is satisfied. Another method is to get the general solution for the inequality, then check with each of the numbers.
The slope-intercept inequality is an equation of the form y < mx + c. The inequality can be reversed, and in both cases can be strict or not. In all cases the equality divides the Cartesian plane into two and the inequality determines which side of the straight line is the valid region, and whether or not the line itself should be included.
Good question.Think about lxl > 3: x can be >3 or goes with or. < goes with and.
whether or not you are still married i suppose.