9x + 9 - 1 = 9x + 8
12x + 6=9x + 27 12x-9x + 6=9x - 9x + 27 subtract 9x from both sides. 3x + 6 = 27 simplify 3x + 6 - 6=27 - 6 subtract 6 from both sides. 3x=21 simplify 3x/3=21/3 divide both sides by 3 x=7 simplify 12(7) + 6=>84+6=>90 9(7) + 27=>63+27=>90 It checks out!
7 plus 7x--2x plus 3 is: 7 + 7x + 2x + 3 = 0 9x + 10 = 0 9x = -10 x = -10/9 = -1 1/9
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
9x+6 = 6x+15 9x-6x = 15-6 3x = 9 x = 3
9x + 9 - 1 = 9x + 8
minus 4 plus 9 = 5, so 5x
5*2+9x-2=0 so, going by BODMAS rule 10+9x-2=0 9x=-10+2 9x=-8 x=-8/9 I think!!
3x + 6x +1 = 10 9x = 10 - 1 9x = 9 x = 1
9 + 5x = -4x + 63 9 + 9x = 63 9x = 54 9x/9 = 54/9 x = 6
8x+9=9x-18+9 = 8x+9=9x-9 = 1x=0 (:
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4
12x + 6=9x + 27 12x-9x + 6=9x - 9x + 27 subtract 9x from both sides. 3x + 6 = 27 simplify 3x + 6 - 6=27 - 6 subtract 6 from both sides. 3x=21 simplify 3x/3=21/3 divide both sides by 3 x=7 simplify 12(7) + 6=>84+6=>90 9(7) + 27=>63+27=>90 It checks out!
It is: 12x+9
[9x-5x+1] + [16x-2x-9] [4x+1] + [14x-9] [18x2+8]
x = 5
9x + 9 = 135 9x = 126 x = 14