x-9y
Your answers are x = 2 & y = 1Original Equationsx - 2y = 03x + 2y = 8Solve for a variable (x)x = 2ySubstitute x with its equation3*(2y) + 2y = 86y + 2y = 88y = 8y = 1Solve for second variablex = 2*(1)x = 2Check your answer(2) - 2*(1) = 03*(2) + 2*(1) = 8
x^(2) - 4y^(2) Before calculating , we note #1 ' There is a negative sign between the two squares. So it will factor #2 ' '4' is the square of '2' . So we can redraw the terms as ( 2y)^2 Hence x^(2) - (2y)^2) This now satisfies the two conditions above. . So it will factor to ( x - 2y)(x + 2y) Note the different signs in each bracket . You hve asked for it to be solved!!! To solve you need to equate the terms to a value. In this case use '0' Hence (x - 2y)(x + 2y) = 0 Taking each bracket in turn x - 2y = 0 x = 2y or 2 = x/y or y = x/2 Then x + 2y = 0 x = -2y or -2/x/y or y = x/-2 Are the possible forms of solution. NB If you have two squared terms and a positive (+) between them, then it does NOT factor. NNB Think of the Pythagorean Equation a^2 + b^2 = h^2 This DOES NOT factor. However a^2 = h^2 - b^2 (Algebraic rearrangement) , DOES factor to a^2 = (h - b)(h + b)
6x+2y=4 gives y=2-(1/3)x
If you mean x+2y = -2 and 3x+4y = 6 then the solutions to the equations are x = 10 and y = -6
2+2y+x+xy=(x+2)(y+1)
0
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
2+2y+x+xy
Can you help me find the value x & Y 3x + 7y = 5 5x-2y = -19
xy(x - 2y)(x + 2y)
(x + 2)(y - 3)
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
If: x-2y = 8 and xy = 24 Then: x = 8+2y and so (8+2y)y = 24 => 8y+2y2-24 = 0 Solving the quadratic equation: y = -6 or y = 2 By substitution points of intersection: (-4, -6) and (12, 2)
x-9y
Your answers are x = 2 & y = 1Original Equationsx - 2y = 03x + 2y = 8Solve for a variable (x)x = 2ySubstitute x with its equation3*(2y) + 2y = 86y + 2y = 88y = 8y = 1Solve for second variablex = 2*(1)x = 2Check your answer(2) - 2*(1) = 03*(2) + 2*(1) = 8
Using: x - 2y = 8 y = (x - 8)/2 Substituting in: xy = 24 => x(x - 8)/2 = 24 => x2 - 8x = 48 => x2 - 8x - 48 = 0 => (x - 12)(x + 4) = 0 => x = 12 or -4 => y = 2 or -6 respectively (since xy = 24) ie the points (12, 2) and (-4, -6)