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3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
13 = 12x - 2y Adding 2y to both sides: 13 + 2y = 12x Subtracting 13 from both sides: 2y = 12x - 13 Divide both sides by 2: y = 6x - 6.5
2y = 4x + 4y = 2x + 2
6x+2y=4 gives y=2-(1/3)x
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
y=16 x= -4
By elimination: x = 3 and y = 0
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
Usually elimination is used on two equations and is called linear combination. You could solve for "y." That is customary. 2x+3y=1 3y=-2y+1 y=(-2/3)x+1/3
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
Solving by the elimination method gives: x = 3 and y = 2
Solving by the elimination method: x = 7 and y = 2
4x-2y = 6 -7x+2y = -15 Add both equations together in order to eliminate y: -3x = -9 Divide both sides by -3 in order to find the value of x: x = 3 Substitute the value of x into the original equations to find the value of y: Solution: x = 3 and y = 3
Add 2y - 4 to each side; 5y - 13 = 0 so y = 2.6