x-9y
8840-026
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
13 = 12x - 2y Adding 2y to both sides: 13 + 2y = 12x Subtracting 13 from both sides: 2y = 12x - 13 Divide both sides by 2: y = 6x - 6.5
2y = 4x + 4y = 2x + 2
6x+2y=4 gives y=2-(1/3)x
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
y=16 x= -4
By elimination: x = 3 and y = 0
Using the elimination method, 3x + (2y) times 18x - 3y - 5 gives the result of 36xy + 3x - 3y - 5.
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
To solve the system of equations using elimination, first write the equations in a standard form. The equations given seem to be misformatted; if we assume they are (3x + 2y = 31) and (5x + 2y = 49), you can eliminate (2y) by subtracting the first equation from the second. This results in (2x = 18), so (x = 9). Substitute (x = 9) back into one of the original equations to find (y).
Usually elimination is used on two equations and is called linear combination. You could solve for "y." That is customary. 2x+3y=1 3y=-2y+1 y=(-2/3)x+1/3
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
Solving by the elimination method: x = 7 and y = 2
Solving by the elimination method gives: x = 3 and y = 2
To solve the simultaneous equations (5x + 2y = 11) and (4x - 3y = 18), we can use the substitution or elimination method. By manipulating the equations, we find that (x = 4) and (y = -3). Thus, the solution to the simultaneous equations is (x = 4) and (y = -3).