You've come to the right place. Our Math staff had a sudden cancellation,
and at the last minute, we were able to add this problem to their schedule.
They have responded with the following solution:
4x + 9 + 3x = 30
Combine the 'x' terms on the left side of the equation:
7x + 9 = 30
Subtract 9 from each side:
7x = 21
Divide each side by 7:
x = 3
OR
4x +9+3x = 30
7x+9 = 30
7x=30-9 (Transposing 9 to RHS)
7x=21
x=21/7 (Transposing 7 to Right Hand Side)
x=3
Hence the required answer is 3.
x = 6 and y = -2
7x+6 = -3x-24 7x+3x = -24-6 10x = -30 x = -3
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
You cannot solve one linear equation in two unknown variables.
x+30 = 3x-50 x-3x = -50-30 -2x = -80 x = 40
x = 6 and y = -2
7x+6 = -3x-24 7x+3x = -24-6 10x = -30 x = -3
23
x=7
x = -8
3
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-3x + 5 = 20 -3x = 15 x = -5
13-3x = 43 -3x = 43-13 -3x = 30 x = -10
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)