5p - 3 = 15
Add 3 to each side:
5p = 18
Divide each side by 5:
p = 18/5 = 3.6
[Kr] 4d10 5s2 5p3
[Kr]4d105s25p3
[Kr]4d105s25p3
The electronic configuration of stibium (antimony) is: [Kr]4d10 5s2 5p3.
[Kr] 4d10 5s2 5p3
There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
Sb (antimony) has 51 electrons. Its noble gas notation is [Kr] 4d10 5s2 5p3
there are 51 electrons in all. So the atomic number of the element is 51 and the element is antimony.
Sb (antimony) has 51 electrons. Its noble gas notation is [Kr] 4d10 5s2 5p3
60 if you allow permutations, 20 if not. 60 is found by suing the permutation function 5P3, and we get 20 simply by dividing by 3 as there will be 3 permutations from a group of 3 numbers while keeping the order the same e.g. (1,2,3) , (2,3,1) and (3,1,2).
Assuming this is your original formula: -3p3+ 5p + -2p2 + -4 - -12p + 5 - -8p3You combine like terms, where the p exponent is the same, to produce:5p3 - 2p2 + 17p + 1
you use nPr, when you want to take note of the order. Example, in choosing between A,B,C,D & E , how many ways can you choose any 3 arranged letters. (This means ABC is different from ACB or BCA or...) Then 5P3. you use nCr , when the order is not important. Example , how many ways can you get three letters from A,B,C,D & E. (here ABC is no different from BAC since you just got A&B&C.) Then 5C3. I got this from yahoo answers :P