There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.
The first digit can be any one of 5 choices. For each of those, the second digit can be any one of 4 choices. For each of those, the third digit can be any one of 3 choices. So the total number of permutations without repetition is 5 x 4 x 3 = 60.
The are 36 permutations of two dice. Of these, 6 permutations have the two dice with the same number, specifically 1+1, 2+2, 3+3, 4+4, 5+5, and 6+6. The probability, then, that two dice rolled will not have the same number is 30 in 36, or 5 in 6, or about 0.8333.
6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations
Permutations are the different arrangements of any number of objects. When we arrange some objects in different orders, we obtain different permutations.Therefore, you can't say "What is the permutation of 5?". To calculate permutations, one has to get the following details:The total number of objects (n) (necessary)The number of objects taken at a time (r) (necessary)Any special conditions mentioned in the question (optional).
There are 5*4*3 = 60 permutations.
There are 7893600 permutations.
6
120
5*4*3*2*1 = 120
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
There are 5,273,912,160 permutations of 5 numbers out of 90.
There are 120 permutations and 5 combinations.
6! Six factorial. 6 * 5 * 4 * 3 * 2 = 720 =====
120.
Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.
Given the individual digits: 4, 6, 9, 1, and 3,the number of 4-digit permutations is (5! / 1!) = (5 x 4 x 3 x 2) = 120 .The number of combinations is [ 5! / (1!4!) ] = 5 .