log5 20 + log5 10 - 3log5 2
= log5 [(20*10)/(2^3)]
= log5 25
= 2 (log5 5)
= 2
log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1
1.268293446
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
8x + -2 = 10 8x = 12 x = 1.5
10+r = 2r Subtract r from both sides:- r = 10
log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1
To solve the equation 3log5 125 - log2 8 = x, you can use the properties of logarithms. First, simplify the logarithmic expressions: 3log5 125 simplifies to log5 (125^3), and log2 8 simplifies to log2 (2^3). This gives you log5 15625 - log2 8 = x. Then, you can combine the logarithms using the quotient rule to get log5 (15625/8) = x. Finally, simplify the expression inside the logarithm to get x = log5 1953.125.
log5 +log2 =log(5x2)=log(10)=log10(10)=1
1.268293446
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
Not enough information to solve
-2
3m plus 19. Change it if I am wrong!
10
x=35
A + 10 = 7.9Subtract 10 from each side:A = 7.9 - 10 = -2.1
-50