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log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1

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Q: Log5 2 plus log5 10 - log5 4?
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How do you solve log5 20 plus log5 10 - 3log5 2?

log5 20 + log5 10 - 3log5 2 = log5 [(20*10)/(2^3)] = log5 25 = 2 (log5 5) = 2


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To solve the equation 3log5 125 - log2 8 = x, you can use the properties of logarithms. First, simplify the logarithmic expressions: 3log5 125 simplifies to log5 (125^3), and log2 8 simplifies to log2 (2^3). This gives you log5 15625 - log2 8 = x. Then, you can combine the logarithms using the quotient rule to get log5 (15625/8) = x. Finally, simplify the expression inside the logarithm to get x = log5 1953.125.


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