Whatever your value of n is, you need to multiply it by 5 and then add 2 to get your answer. Below is how to solve it algebraically: 5n+2 = 0 (it needs to be equal to something in order to solve it, so I assumed that it equals zero) 5n = -2 n = -2/5
n=3,y=4 2(n+3y)=30
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
n = 8 Solution Steps Step 1 Multiply on both sides 1/4 n * 4 = 2 * 4 Step 2 Simplify the left side n = 2 * 4 Solution n = 8
(n+4)2 = 36 This is your equation. To solve for it square root of both sides then minus the 4 from both sides and you find your "n" n+4= 6 n=2 Your variable equals 2
(n-2)x180
Solve for n. 2n+3=0 2n=-3 n=-3/2
If the question means solve 1+2+...+60 then 1+2+...+n = n(n+1)/2 for any integer n>0 So for n= 60 the sum is 60*61/2 = 30*61 = 1830
I'll represent the unknown value of the number with the variable 'n'.9 + (n/2) = 24This is the equation, now to solve it, solve for n.18/2 + n/2 = 24(18+n)/2 = 2418 + n = 48n = 30
n + 2 = 5, solve for n.n = 5 - 2n = 3
Whatever your value of n is, you need to multiply it by 5 and then add 2 to get your answer. Below is how to solve it algebraically: 5n+2 = 0 (it needs to be equal to something in order to solve it, so I assumed that it equals zero) 5n = -2 n = -2/5
(n+2)/n = 110Multiply each side by 'n':n + 2 = 110nSubtract n from each side:2 = 109nDivide each side by 109:n = 2/109
1/5
20 sides. The interior angles of a polygon add up to 180(n-2). We solve: 180(n-2) = 3960 n-2 = 22 n-2(+2) = 22(+2) n=24
Well, isn't that a happy little equation we have here! To solve 3n - 2n, all you need to do is subtract 2n from 3n, which leaves you with n. So, the answer is simply n, a beautiful and peaceful solution. Just like painting a serene landscape, sometimes the simplest answers can bring the most joy.
A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.A polygon with n sides has n*(n-3)/2 diagonals.So you need to solve n*(n-3)/2 = 54n2 - 3n - 108 = 0 which has the solutions n = 12 or n = -9.Since a polygon cannot have a negative number of sides, the answer is 12.
n=3,y=4 2(n+3y)=30