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y/x is a constant; so first of you can solve for this constant. y/x=6/-3, or y/x=-2 y/4=-2 y=-8
substitute 0 for y and solve for x. then substitute x for 0 and solve for why and you have the x and y coordinates
Sum = addition Difference = subtraction Say your first number is x and your second number is y. So: x+y = 10 and x-y = 20 Solve for one variable for one of the above equations and substitute that variable into the other equation: x = 10-y (10-y)-y = 20 10-2y = 20 Get y by itself: -2y = 20-10 -2y = 10 Solve for y: -2y/-2 = 10/-2 y = -5 To solve for x: x = 10-y x = 10-(-5) x = 10+5 x = 15 Therefore, the two numbers you are looking for are -5 and 15.
x-intercept: 1. substitute 0 for y 2. solve for x y-intercept: 1. substitute 0 for x 2. solve for y
First, solve for y.y=-8xif x=2, then y=-16.
If you mean: y-6-2(x+2) then it can be simplified to y-2x-10
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To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
y=x+2 is also equal to y-2=xy = x + 2 , they have to be given what either x or y is and then you'd solve for the other one
To find the inverse you switch the x and the y and then solve for y. x=2 radical( y + 3) radical(y + 3) = x/2 y+3= (x/2)² y = (x/2)² -3 So the answer is y = (x/2)² -3
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The y-intercept is where x = 0. Therefore, you can write:f(x) = 5(x-2)y = 5(x-2)... then you can replace "x" by zero, and solve for y.
Put in zero for the x value and solve for y. Example: x^2 + y^2 = 4 If x=0, y^2=4 So y = 2 or -2
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Set up a system of equations. x+y= 25 & x^2 - y^2 = 75. Rearrange the first equation to isolate x.... x=25-y Now substitute x in to the 2nd equation. (25-y)^2 - y^2 = 75. Solve that equation to get the value of y and plug y into x+y=25 and solve for x.