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(3n+2)(n+1)
That factors to (2n + 1)(n + 2)
(4n - 1)(3n + 2)
Whatever your value of n is, you need to multiply it by 5 and then add 2 to get your answer. Below is how to solve it algebraically: 5n+2 = 0 (it needs to be equal to something in order to solve it, so I assumed that it equals zero) 5n = -2 n = -2/5
It is impossible to read exactly what the expression is - it looks like there are some operators missing from expression: between the 2 and 5n, between the 5 and n, between the 3 and n. As written it looks like: 25n + 3 + 5n + 3n + 2 = 33n + 5 which is not divisible by 17 for n = 1 (at least). Please re-ask your question spelling out every operator, eg 2 bracket 5n plus 3 close bracket plus 3 minus n...
5n-2+2=4n 5n=4n n=0
5n - 4 = 10n + 6-5n = 10n = -2
5n+6=(-4) n= (-2)
5n+15 = 25 5n = 25-15 5n = 10 n = 2
(3n+2)(n+1)
5n+6=-45n=-10n=-2
A - B = -3n + 2 - (5n - 7) = -3n + 2 - 5n + 7 = 9 - 8n
68
8n-2+4n = 66-5n 8n+4n+5n = 66+2 17n = 68 n = 4
That factors to (2n + 1)(n + 2)
22n + 2.
4n