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How do you get the y intercept without having to draw a graph?
You can put the equation into slope-intercept form and the answer is right there, or you can put it in standard form and make the x coefficient and x "disappear" and solve the equation by dividing the number with y by the number on the other side of the equation.
How do you graph 3x-y equals 6?
-3
Does y equals 5 have a slope?
Yes.Technically all equations in Slope Intercept Form have slopes and y intercepts.Slope Intercept Form is y = mx + b. (Where mx is the slope of the line and b is the y intercept.)In your particular equation you can infer that 5 is the y intercept because you don't have your x variable there.The slope in this case is 0, meaning your line is going to be horizontal across point (0, 5). (The y intercept)Another way to write this equation which will make finding the slope much easier is y = 0x + 5. Because the equation says 0x, there is no need to put it.It's like the difference between just saying x or saying 1x.
Does a change in the y intercept make the line more or less steep?
Neither. Changing the y-intercept will simply move the line up or down the y-axis.The "steepness" is all a matter of the slope.Now that we said that, we can think of a situation where changing the y-interceptwould change the slope of the line:That would be where you were given the y-intercept and one other point, and youhave to find the slope, or find the equation, or draw the line.If somebody sneaks in and changes the y-intercept, but leaves the other point rightwhere it is, then the slope of the line changes, (and so does the equation).
How do you graph the equation y equals x minus 1?
Well that is in y intercept slope form so what you do is you make an x/y table. putting -2,-1,0,1,2 on the x axis and then multiply each of them by 1 and -1. then they form ordered pairs and you graph them! hope that helped!! An easier way to graph it would be to do this. The (x) is the slope and the (minus 1)(-1) is the y-intercept. So first you would go down one on the graph you made, (on the y-axis), and put a dot on the point (0,-1). Then by graphing the (x), you would go up 1, then right 1, up 1, right 1, and so on, until you reach the edge of the graph, and then trace a straight line through the points. Then to properly detail it, put an arrow on each end of the line. and write the equation (such as the one you graphed), above the lined equation. I Think you should get a 100% on that, your welcome
