Reflection across the y-axis changes the sign of the x - coordinate only, that is, (x, y) becomes (-x, y).
y' = y, x' = -x.
Each reflection produces a mirror image.=================================Answer #2:With the initial point at (0, 0) ... the origin of coordinates ...-- the first reflection, across x = -3, moves the point to (-6, 0), and-- the second reflection, around y = -3, moves it to (-6, -6) .
Yes. Suppose the point is P = (x, y). Its reflection, in the x-axis is Q = (x, -y) and then |PQ| = 2y.
The points after reflection will follow points equal but different direction, to the path followed before the reflection. So, if the line would cover 3.5 on the x and 5 on the y; it will reflect symmetrically giving you the formula to get your answer.
If a point is reflected about the y-axis then the y co-ordinate remains unchanged but the x co-ordinate changes its sign. Examples : (3,7) after reflection becomes (-3,7) (-2, 5) after reflection becomes (2,5)
y' = y, x' = -x.
If your points are (p,f), they become (p,-f).
Example: if you have a point with the coordinates (2,4), a reflection over the y-axis will result in the point with coordinates (-2,4).
Each reflection produces a mirror image.=================================Answer #2:With the initial point at (0, 0) ... the origin of coordinates ...-- the first reflection, across x = -3, moves the point to (-6, 0), and-- the second reflection, around y = -3, moves it to (-6, -6) .
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).
It is (6, -1).
Yes, it will.
The answer is simple, it is: (-1, -4) EZ(Easy)
me no no
Yes. Suppose the point is P = (x, y). Its reflection, in the x-axis is Q = (x, -y) and then |PQ| = 2y.
In order to answer that, I need to know the position of ABCD with respect tothe x-axis before the reflection process begins.But wait! What light through yonder window breaks ? ! On second thought, maybe I don't.If D is the point (x, y) before the reflection, then D' is the point (x, -y) after it.
The points after reflection will follow points equal but different direction, to the path followed before the reflection. So, if the line would cover 3.5 on the x and 5 on the y; it will reflect symmetrically giving you the formula to get your answer.