If your points are (p,f), they become (p,-f).
In order to answer that, I need to know the position of ABCD with respect tothe x-axis before the reflection process begins.But wait! What light through yonder window breaks ? ! On second thought, maybe I don't.If D is the point (x, y) before the reflection, then D' is the point (x, -y) after it.
The reflection of a point across the y-axis involves changing the sign of the x-coordinate while keeping the y-coordinate the same. In this case, the point (-1, -5) will reflect to (1, -5) across the y-axis. This is because the x-coordinate changes from -1 to 1, while the y-coordinate remains -5.
The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.
(-3,1) progress learning/ usatestprep
For a reflection over the x axis, leave the x coordinate unchanged and change the sign of the y coordinate.For a reflection over the y axis, leave the y coordinate unchanged and change the sign of the x coordinate.
To reflect a point across the origin, you simply change the sign of both the x- and y-coordinates of the point. This transformation involves multiplying the coordinates by -1.
y' = y, x' = -x.
Reflection across the y-axis changes the sign of the x - coordinate only, that is, (x, y) becomes (-x, y).
Example: if you have a point with the coordinates (2,4), a reflection over the y-axis will result in the point with coordinates (-2,4).
Each reflection produces a mirror image.=================================Answer #2:With the initial point at (0, 0) ... the origin of coordinates ...-- the first reflection, across x = -3, moves the point to (-6, 0), and-- the second reflection, around y = -3, moves it to (-6, -6) .
If the coordinates of a point, before reflection, were (p, q) then after reflection, they will be (-p, q).
It is (6, -1).
The answer is simple, it is: (-1, -4) EZ(Easy)
Yes, it will.
me no no
Yes. Suppose the point is P = (x, y). Its reflection, in the x-axis is Q = (x, -y) and then |PQ| = 2y.
Slope. I'm pretty sure.