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Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.

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Q: How is the graph of y 4x2 1 different from the graph of y 4x2?
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How does the graph of y 4x2 compare to the graph of y x2?

Their noses are both at the origin, and they both open upward, but y=4x2 is a much skinnier parabola.


What is the range of the function y -4x2 1?

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Find vertex and roots of y equals 4x squared plus 6?

y = 4x2 + 6 ory = 4x2 + 0x + 6, where a = 4, b = 0 and c = 6x-coordinate of the vertex = -b/2a = -0/2(4) = 0y-coordinate of the vertex = 4(02) + 6 = 6vertex is (0, 6)(Or you can say: Since the vertex of y = x is (0, 0), and this graph is shifted 6 units upward in the y-axis, then the vertex of y = x + 6 would be (0, 0 + 6) or (0, 6)Substitute 0 for y in order to find the roots.y = 4x2 + 60 = 4x2 + 60 - 6 = 4x2 + 6 - 6-6 = 4x2-6/4 = 4x2/4- 6/4 = x2± √(-6/4) = x± [√(6/4)]i = x x = [(1/2)√6]i or x = - [(1/2)√6]i


What is the square root of -4x2?

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How do you write 4x2 plus y equals 16 using function notation?

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Y equals 4X2 plus 3x plus 8?

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How is y equals x - 1 different from the graph of y equals x?

The slope or gradient is the same and would run parallel but the intercept on the y axis would be at -1