When you have a choice of 7 digits, and cannot repeat any digit, then the first number can be chosen in 7 ways, the second can be chosen in 6 and the third can be chosen in 5.
7 x 6 x 5 = 210
There are 2000 such numbers.
# 230 # 203 # 320 # 302
With repetition, 94 = 6561. Without repetition, 9*8*7*6 = 3024.
There are 60480 numbers.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
64 if repetition is allowed.24 if repetition is not allowed.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
Six (6)
9*8*7 = 504 of them.
3*2*1 = 6 of them.
It is 415968.
There are 2000 such numbers.
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
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# 230 # 203 # 320 # 302