246 248 264 268 284 286 426 428 462 468 482 486 624 628 642 648 682 684 824 826 842 826 862 864
With repetition, there are 86 ( = 262144) such numbers. Without repetition, there are still 8!/2! = 20160.
There are 2000 such numbers.
If the number can contain repeated digits, the answer is 800000. Without repetition, there are 483840.
Assuming you meant the largest 3 digit number without repetition:Largest 4 digit without repetition = 9876Largest 3 digit = 987⇒ difference = 9876 - 987 = 8889
If the first number can not be zero then it is 9x9x8x7x6=27,216 If the first number can be zero then it would be 10x9x8x7x6=41,160
1
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
With repetition, there are 86 ( = 262144) such numbers. Without repetition, there are still 8!/2! = 20160.
There are 4*4*3*2*1 = 96 such numbers.
There are 2000 such numbers.
There are 60 such numbers.
If you consider whole numbers, the largest 5 digit number with repetition is 99999 the smallest 4 digit number without repetition is -9876 Their difference is 99999 - (-9876) = 99999 + 9876 = 109875.
9999-1023 = 8976
It is 720.
To calculate the number of four-digit numbers that can be made using the digits 1, 4, 5, and 9 without repetition, we use the permutation formula. Since there are 4 digits to choose from for the first digit, 3 for the second, 2 for the third, and 1 for the fourth, the total number of permutations is 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different four-digit numbers that can be formed using the digits 1, 4, 5, and 9 without repetition.
8889
9774