For repeating digits = 9 * 10 *10 = 900
For non-repeating digits = 9 * 9 * 8 = 728
hope the answer helped! have a great day! :D
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But it probably did not because it is wrong. The answer relates to the number of PERMUTATIONS which is quite different from COMBINATIONS. In a combination, the order of digits does not matter so that 123 is the same as 312 etc. Because the order of the digits is irrelevant, there can be no "leading" digit and so the absence or presence of 0s makes no difference.
Assuming the 6 numbers are all distinct, the answer is (6*5*4)/(3*2*1) = 20
There are 15 combinations.
9999
there are 63 combos
40 dhjfdsm dlgkDRFRt
There are an infinite number of numbers.
None. You do not have enough numbers to make even one combination.
10C6 = 210
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
There are 15 combinations.
9999
Only 1. In a combination the order of the numbers or other characters does not matter. So, the combination 135.6 is the same as the combination 6.153
Since there are infinitely many prime numbers, there can be no such number.
4 of them. In a combination the order of the numbers does not matter.
It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.
there are 63 combos
There are: 7C6 = 7
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.