There are 15 combinations.
Well honey, there are 4 numbers in your combination, so it's as simple as 4 factorial, which is 4 x 3 x 2 x 1, giving you a total of 24 combinations using the numbers 1, 4, 6, and 9. That's all there is to it, no need to complicate things.
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
Combination codes are actually permutations and notcombinations. The number of codes depends on how long (how many digits) the code is and that is not specified in the question. Also, the number of codes depends on whether or not the digits may be repeated - again, not specified in the question.There are 24 permutations that use each of the numbers once in a 4-digit code.There are infinitely many codes in which the numbers can be used repeatedly, each an infinite number of times!
98,706,816
There are infinitely many numbers divisible by 5 and 4. 680 is one of them.
-- 4 numbers can be lined up in 24 different ways-- If the order doesn't matter, then there's only one4-number combination of 4 numbers.
4 of them. In a combination the order of the numbers does not matter.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
None. You do not have enough numbers to make even one combination.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
Assuming each number can be used more than once.... 2401 possible combinations.
they are 24 you can make with the numbers 1-4 or any other 4 digits here they are123412431432142313421324213421432431241323412314312431423421341232413214423142134312432141324123* * * * *WRONG!These are permutations, not combinations. In a combination theorder of the digits does not matter so there is only one combination of 4 digits out of 4.
To find the number of 4-number combinations from a set of 5 numbers, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of items to choose from, and ( k ) is the number of items to choose. Here, ( n = 5 ) and ( k = 4 ). Thus, ( C(5, 4) = \frac{5!}{4!(5-4)!} = \frac{5}{1} = 5 ). Therefore, there are 5 different 4-number combinations that can be formed from 5 numbers.
Well honey, there are 4 numbers in your combination, so it's as simple as 4 factorial, which is 4 x 3 x 2 x 1, giving you a total of 24 combinations using the numbers 1, 4, 6, and 9. That's all there is to it, no need to complicate things.
4
4
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.