We figure out how many possibilities exist for each digit, and multiply them all together. Think of the digits as slots that need to be filled: _ _ _ _ The first digit can be anything but 0; 0345 is not a 4-digit number, for example. So there are 9 choices for the first digit. All the subsequent digits can be anything from 0-9; there are 10 choices for digits two, three, and four. So there are 9x10x10x10 = 9000 possible numbers with 4 digits.
There are 60480 numbers.
There are 4^6 = 4096 such numbers.
If the digits are all different then 18. Otherwise, 192.
48 of them if digits may not be repeated. 100 if they can.
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
99999
There are 60480 numbers.
There are 4^6 = 4096 such numbers.
8.
If the digits are all different then 18. Otherwise, 192.
15 of them.
27
6
More than one
48 of them if digits may not be repeated. 100 if they can.
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
There are 2000 such numbers.