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How many 5-digit numbers can be formed using the digits 0 1 2 3 4 5 6 if repetitions are not allowed?
Wiki User
∙ 15y ago
288
000, 001, 002, 003, 004, 005, 006, 010, 011, 012, 013, 014, 015, 016, 020, 021, 022, 023, 024, 025, 026, 030, 031, 032, 033, 034, 035, 036, 040, 041, 042, 043, 044, 045, 046, 050, 051, 052, 053, 054, 055, 056, 060, 061, 062, 063, 064, 065, 066
x 6
Unless you mean all numbers in the string must be unique, excluding numbers like 000 and 001, then it's
180
or
012, 013, 014, 015, 016, 021, 023, 024, 025, 026, 031, 032, 034, 035, 036, 041, 042, 043, 045, 046, 051, 052, 053, 054, 056, 061, 062, 063, 064, 065
x 6
Wiki User
∙ 13y ago
Wiki User
∙ 15y ago2520 numbers.
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How many 3-digit codes using digits 0 through 9 are possible if repetitions are allowed?
10,000
How many numbers less than 500 can be formed using the digits 12345 and 6 without repetitions?
There is no limitation given to the number of digits in the number, thus: For 3 digit numbers: to be less than 500 the first digit can be only one of {1, 2, 3, 4} leading to 4 × 5 × 4 = 80 numbers For 2 digit numbers: they are all less than 500, and there are 6 × 5 = 30 numbers For 1 digit numbers: they are all less than 500, and there are 6 numbers Thus there are in total 80 + 30 + 6 = 116 numbers that can be made form the digits {1, 2, 3, 4, 5 ,6} without repetitions that are less than 500.
How many 2 digit numbers can be formed using the digits 1 3 5 7 9 and 0 if repeating is not allowed?
There are 25 such numbers.
How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many four digit numbers can be formed from the digits 1 and 2 if repetitions are allowed?
pizza
How many digits numbers each less than 500 can be formed from the digits 13467 if repetitions is allowed?
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many 6 digit numbers can be formed with 1 to 45 digits?
Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 if repetitions of digits are allowed?
2,401
How many 4 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?
10,000
How many 5-digit numbers can be formed using the digits 0 1 2 3 4 5 if repetitions are allowed exactly divided by 4?
5^4
How many 3 digit numbers can be formed from the digits 357 with any digit repeated?
27 three digit numbers from the digits 3, 5, 7 including repetitions.
How many 3-digit codes using digits 0 through 9 are possible if repetitions are allowed?
10,000
How many 3 digit codes using the digits 0 9 are possible if repetitions are allowed?
900 ,999 ,909
How many different combinations can be created using the digits 0-9 is the first digit cannot be 0 and repetitions are not allowed?
8877690
How many six digit numbers can be formed using the digits 0123456789 Example equals 123456 or 098765?
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
