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288

000, 001, 002, 003, 004, 005, 006, 010, 011, 012, 013, 014, 015, 016, 020, 021, 022, 023, 024, 025, 026, 030, 031, 032, 033, 034, 035, 036, 040, 041, 042, 043, 044, 045, 046, 050, 051, 052, 053, 054, 055, 056, 060, 061, 062, 063, 064, 065, 066

x 6

Unless you mean all numbers in the string must be unique, excluding numbers like 000 and 001, then it's

180

or

012, 013, 014, 015, 016, 021, 023, 024, 025, 026, 031, 032, 034, 035, 036, 041, 042, 043, 045, 046, 051, 052, 053, 054, 056, 061, 062, 063, 064, 065

x 6

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2520 numbers.

Q: How many 5-digit numbers can be formed using the digits 0 1 2 3 4 5 6 if repetitions are not allowed?

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10,000

There is no limitation given to the number of digits in the number, thus: For 3 digit numbers: to be less than 500 the first digit can be only one of {1, 2, 3, 4} leading to 4 × 5 × 4 = 80 numbers For 2 digit numbers: they are all less than 500, and there are 6 × 5 = 30 numbers For 1 digit numbers: they are all less than 500, and there are 6 numbers Thus there are in total 80 + 30 + 6 = 116 numbers that can be made form the digits {1, 2, 3, 4, 5 ,6} without repetitions that are less than 500.

There are 25 such numbers.

9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.

You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.

Related questions

pizza

There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.

Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200

2,401

10,000

5^4

10,000

27 three digit numbers from the digits 3, 5, 7 including repetitions.

900 ,999 ,909

8877690

The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).