The only way to produce 4 as a product of digits is to have either a '4'
or else '2 x 2' among the digits, and ' 1 ' for all the rest of them.
Possibilities that include a '4':
11114
11141
11411
14111
41111
. . . . . . . . . 5 possibilities
Possibilities that include a pair of 2s :
11122
11212
12112
21112
11221
12121
21121
12211
21211
22111
. . . . . . . . . 10 possibilities
Total = 5 + 10 = 15 possibilities
15 1 x 5 = 5, and 5 x 3 = 15
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
A two digit number whose two digits added together equal 42 and multiplied together equal 82
79
Two (or four) digits added together cannot equal 42. Two-digit numbers multiplied together cannot equal 82.
121
The only three-digit number that fits the criteria of being a square number and having a product of its digits equal to two is 128. This is because 128 is a square number (11^2 = 121, 12^2 = 144) and the product of its digits (1 x 2 x 8) equals 16, which is not equal to two. Therefore, there is no three-digit number that meets all the given conditions.
1
There are 15 of them.
15 1 x 5 = 5, and 5 x 3 = 15
29 2 * 9 = 18 2 + 9 = 11 18 - 11 = 7
21 and 20
The Answer is 36 btw. 3 + 6 = 9 3 x 6 = 2(3x6) 2(18) = 36
412
A two digit number whose two digits added together equal 42 and multiplied together equal 82
55 52+52 = 50
Only if the final digit, after the decimal point, is zero.