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How many 5 digit numbers can be formed using 0 2 3 4 and 5 when repetition is allowed such that number formed is divisible by 2 or 5 or both?
Wiki User
∙ 12y ago
2000 is the answer.
(explanation)
There are four choices for the first digit since it cannot be zero . ( We do not
consider something like 01234 to be a 5-digit number.)
Any of the five choices will do for the second, third and fourth digits.
The last digit must be 0,2,4, or 5 to make it divisible by 2 or 5 or both.
Therefore, there are 4 x 5 x 5 x 5 x 4 = 2000 possibilities in all.
Wiki User
∙ 12y ago
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How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
How many 3 digit numbers can be formed from digits 0 1 2 3 4 5 6 7 8 9 and what are the results?
If repetition is allowed and leading zeros are allowed, then you have 000 to 999, which is 1,000 possibilities (I will not list them here). If no leading zeros are allowed, then you have 100 through 999, so there are 900 possibilities. If there are other restrictions, such as no repetition, then I'll refer you to the related link at MathsIsFun.com
How many five digit numbers can be formed using the digits 0 2 3 4 and 5 when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
"Divisible by two" means the number can end with 0,2, or 4."Divisible by five" means the number can end with 0 or 5.Combined that means the ONLY digit the number cannot end with is 3; it can end with any of the other four.Also, I'm presuming that it's not a "five digit number" if it starts with a 0, so only four of the digits are legal there.All told, there are 4 x 5 x 5 x 5 x 4 possibilities. That's 2000 different possible numbers.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3 digit numbers are formed from 1234567?
If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210
How many 3 digit numbers can be formed from the digits 1234?
64 if repetition is allowed.24 if repetition is not allowed.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 3 digit numbers can be formed with set 15678 if repetition is allowed?
There are 5*5*5 = 125 such numbers.
How many 3 digit numbers can be formed from 6 single digit numbers if repeats are allowed?
if the repetition is allowed the there is 6*6*6 possible ways = 216
How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?
125
What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?
It is 415968.
How many different two digit numbers can be formed using the digits 2 3 5 6 8?
20 of them, if repetition is not allowed.
How many different positive integers less than 2000 can be formed by using digits 123 and 4?
64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.64 if repetition is allowed, 6 otherwise.
How many 9 digit numbers which are divisible by 4 can be formed by using the digits 1 to 5 if repetition of digits is not allowed?
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
