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How many 5 number combinations of one and two digits can be made from 1-69 no repeated numbers in each 5 number combinations Example 1-2-3-4-5...1-3-4-5-6...1-4-5-6-7?
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∙ 8y ago
There are 11,238,513 of them.
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∙ 8y ago
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How many number combinations are there in 0-9999?
9999
Which 4-digit numbers can be formed by the digits 1 2 3 4 5 6 7 8 9 0?
This permutation problem depends on whether the numbers are allowed to be repeated. If they are, there are a possible 9999 numbers, starting with 0001 and running sequentially to 9999. If they are not allowed to be repeated, there are a possible 5040 combinations.
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many 4 number combinations are the in the numbers 1 to 10?
First figure in combination can be any of 10, second can be any of remaining 9, third any of remaining 8 and fourth any of remaining 7 so total of possibilities is 10 x 9 x 8 x 7 ie 5040.This assumes no repeating digits, in that case possibilities would be 10 to the fourth power ie 10000.----------------------------------------------------------------------------------------------The question asks for number of combinations. The above result of 5040 is the number of 4 number permutations that can be obtain from the numbers 1 to 10.The number of different 4 number combinations that can be obtain from the numbers1 to 10 is: 10C4 = 10!/(4!∙6!) = 210 different 4 number combinations.If repetition of numbers in the 4 number combination are allowed we have to ad:with 2 numbers repeated; 3∙10C3 = 3(120) = 360with 3 numbers repeated; 2∙10C2 = 2(45) = 90with 4 numbers repeated; 10with two sets of 2 numbers repeated; 10C2 = 45This gives a total of 4 number combinations with repetition of numbers allowed of:210 + 360 + 90 + 10 + 45 = 715 different 4 number combinations.
How many combinations of 6 are there for numbers 1-36?
There are 1,947,792 combinations of 6 numbers out of 36 numbers.
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many combinations of 2 numbers are there in 6 numbers?
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
How many different 4 digit combinations are there for numbers 1 2 3 (assuming all three numbers are used and no numbers can be repeated more than once) (For example, 1233 is acceptable, but 1133 is not.)?
NOT AN ANSWER:More acceptable combinations:1231 3213 2321More unacceptable combinations:1112 2222 3113Thanks.
What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
If using the numbers 1 through 9 how many different 3 digit combinations can be made?
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
What are the Possible combinations of numbers 0 through 9 if any numbers can be repeated in the combination?
How many numbers per combination?
How many number combinations are there in 0-9999?
9999
What are the possible combinations of the digits 0 through 9 if number may be repeated in the sequence?
Infinite. If numbers can be repeated, the list could go on nonstop.
What is the number of possible 9 digit social security numbers if the digits can't be repeated?
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
How many different 4 digit combinations are there for numbers 1 2 3 4 5 and last numbers are 4 5 no restrictions numbers can be repeated?
9
What combinations can you make with numbers 1 4 7 2 5 8 0?
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
How many possible 4 number combinations can you get using numbers 0-9?
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
