answersLogoWhite

0

There are 4845 ways to choose 4 people out of 20

20 choose 4 = 20! / (4!16!)

User Avatar

Wiki User

11y ago

What else can I help you with?

Related Questions

How many 3-person committees can be formed in a club of 8 members?

120


How many different two person committees can be formed from a group of six people?

To determine the number of different two-person committees that can be formed from a group of six people, we use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people and ( k ) is the number of people to choose. Here, ( n = 6 ) and ( k = 2 ). Thus, the number of combinations is ( C(6, 2) = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 ). Therefore, 15 different two-person committees can be formed.


How many combinations of 4 students can you get from a 5 person swimming team?

Any combination of 5 students leaves one student out. Since there are 5 possible students to leave out, the number of combinations of all but one student is 5.


How many 6 person committees can be formed out of 16 people?

There are 16C6 = 16*15*14*13*12*11/(6*5*4*3*2*1) possible committees. That is, 8,008 of them.


How many three person committees can be chosen from a class of twenty five students?

Since the order doesn't matter, this is a combination problem.25C3 = 25*24*23/3*2*1 = 25*4*23 = 2300 committees.


How many 6 person committees can be formed from a group of 16?

They can't be split evenly into groups of six. Sixteen people can split into two groups of six, and there will be four people left over.


How many different four person committees can be formed from a group of 9 people?

(9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126committees.


How many 5 person committees can be selected from nine people?

To determine how many 5-person committees can be formed from nine people, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of people, and ( k ) is the number of people to choose. In this case, ( n = 9 ) and ( k = 5 ). Thus, the number of ways to select the committee is ( C(9, 5) = \frac{9!}{5!(9-5)!} = \frac{9!}{5!4!} = 126 ). Therefore, there are 126 different 5-person committees possible.


How many two person committees can be chosen from a group of nine people?

72


How many combinations can a particular person be always included Choosing 2 people out of 10?

9 combinations - the key person and one of the remaining nine.


How many 4-person committees are possible from a group of 9 people if there are no restrictions?

-5


How many committees does a person in the Senate serve on?

There is no set number. It could be none at all.