7,17,27,37,47,57,67,70,71,72,73,74,75,76,77(two sevens),78,79,87,97=20 times
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what is the unit digit of the product if hundred 7"s r multiplied
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
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7,17,27,37,47,57,67,70,71,72,73,74,75,76,77(two sevens),78,79,87,97=20 times
There can be a maximum of 2 electrons in the 7s orbital, following the Pauli exclusion principle which states that each orbital can hold a maximum of 2 electrons with opposite spins.
5.28751 7s equals 37.
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
There is only one orbital in the 7s sublevel. The "7" corresponds to the principal quantum number and "s" indicates the sublevel shape, which is spherical.
7.143, approximately. 50 ÷ 7 = 7 with remainder 1
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
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