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a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321

so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999,

so there are 8999 palindromic 8 digits number

(I assumed that 00011000 is not to be considered as a valid 8 digit number)

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Q: How many 8 digit palindromic numbers are there?

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There are 8*8 = 64 such numbers.

The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers

well, i think if you use this you can find out. A = 1-9 ,B = 0-9 , C = 0-9 , D = 0-9 , E = 0-9 for 2digit numbers = A A for 3 digit numbers = A B A for 4 digit numbers = A B B A and so on till you get to for 8 digit numbers = A B C D D C B A for 9 digit numbers = A B C D E D C B A and last for 10 digit number = A B C D E E D C B A this should work...

9 x 9 x 8 x 7 = 4,536

13

Related questions

8

1001 - 1991, etc = 10, x (2,3,4,5,6,7,8,9) 8 = 80

The number is 222.

All one digit numbers are palindromes.Cubic numbers are generally understood to be cubes of integers. So the numbers, 1 and 8 are both palindromic cubes.

90(:

-5

There are 8*8 = 64 such numbers.

The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers

90

none

There are 112 such numbers.

512

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