There are more 12-digit palindromic numbers than 11-digit palindromic numbers. This is because the number of possible 12-digit palindromic numbers is greater than the number of possible 11-digit palindromic numbers. In general, the number of palindromic numbers of length n is 9 * 10^((n-1)/2), so for 11-digit palindromic numbers, there are 9 * 10^5 = 900,000 possibilities, while for 12-digit palindromic numbers, there are 9 * 10^6 = 9,000,000 possibilities.
90
9
11
There are 900000 of them.
there are 10 palindromic numbers between 9000 and 10000 9009,9119,9229,9339,9449,9559,9669,9779,9889,9999!!!
No.
90
9
11
There are 900000 of them.
11
1 to 1000. Pilandromic 108
6,1,8
Oh, dude, there are 90 three-digit palindromic numbers. You see, a three-digit palindrome has the form "ABA," where A and B can be any digit from 1 to 9. So, you just multiply the possibilities for A and B, which is 9 choices each, and voilà, you get 9 x 10 = 90. Easy peasy, lemon squeezy!
There are 11520 of them.
To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.