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With a Latin alphabet of 26 letters and the 10 digits 0...9, and allowing for repeats, you get:

36^4 = 36 × 36 × 36 × 36 = 1,679,616 combinations.

If you were to include both lower and upper case characters, the number of possible combinations goes up (due to 26 lower case letters + 26 upper case letters + 10 digits = 62 characters to choose from):

62^4 = 14,776,336.

Q: How many possible alpha numeric combinations are there using all letters for 4 characters?

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im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.

There are only alphabetic combinations since there are no numeric characters in letters.The answer assumes thatyou mean the modern Roman alphabet,letters may not be repeatedupper case and lower case letters are considered to be the same,you did mean combinations and not permutations.Then the answer is 26C5 = 26*25*24*23*22/(5*4*3*2*1) = 65,780

36*36*36*36*36*36

This depends what you define as a "Letter". Are you stricly talking about the 26 characters in the alphabet [a-z], or do you consider "A" not the same as "a"? If capitalization matters, we now have 52 possible values for the first character. What about numeric digits [0-9]? If they count, there are 62 possible values for each character. Maybe some special characters can be used, but we won't delve into those. Therefore, if the length of your string is 6 "Letters" and each letter may be any one of 62 values... use the following calculation: (62) x (62) x (62) x (62) x (62) x (62) = 56,800,235,584 total combinations Hypothetically if you could not use the same character twice, you would have less possible combinations: 62! - 56! is the same as: (62) x (61) x (60) x (59) x (58) x (57) = 44,261,653,680 total combinations

Algebraic phrase is a mathematical expression which substitutes characters and letters for a certain numeric value. For example a=b+c, if b=2 and c=3, then a=5.

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it is 26

26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336

im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.

There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676

There are only alphabetic combinations since there are no numeric characters in letters.The answer assumes thatyou mean the modern Roman alphabet,letters may not be repeatedupper case and lower case letters are considered to be the same,you did mean combinations and not permutations.Then the answer is 26C5 = 26*25*24*23*22/(5*4*3*2*1) = 65,780

36*36*36*36*36*36

Decide what symbols you want to allow. For example: 26 uppercase letters + 26 lowercase letters + 10 digits = 62. Or less, if you don't want to distinguish uppercase and lowercase; or more, if you want to allow certain special symbols such as spaces, hyphens, etc. Raise this number to the sixth power, if you use 6 characters.

3.918208205 X 10^11 I think but I'm stupid so probably wrong

Letters and numbers only. No symbols, punctuation, or special characters. IE abcdefghijklmnopqrtsuvwxyz1234567890

The term alpha characters refers to those characters that are letters. This is in contrast with numeric characters, which are numbers.

Letters - 26Numbers - 10Total chacters - 36If characters can be repeated (QQ and 44 are acceptable): 36 x 36 = 1,296If characters can't be repeated (GG and 99 not acceptable): 36 x 35 = 1,260If characters can't be repeated and the sequencedoesn't matter (X7 and 7X are considered to be the same): 630

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